49w^2-7w-20=0

Solution for 49w^2-7w-20=0 equation:

49w^2-7w-20=0

a = 49; b = -7; c = -20;
Δ = b2-4ac
Δ = -72-4·49·(-20)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-63}{2*49}=\frac{-56}{98}
=-4/7
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+63}{2*49}=\frac{70}{98}
=5/7
$